The description of behaviour is incorrect, the virtual base gets
assigned before entering the bodies of A::operator= and B::operator=,
not after.

The example is also ill-formed (passing a string literal to char*) and
undefined (missing return from Base::operator=).

Signed-off-by: Jonathan Wakely <jwak...@redhat.com>

gcc/ChangeLog:

        PR c++/60318
        * doc/trouble.texi (Copy Assignment): Fix description of
        behaviour and fix code in example.

OK for trunk and all active branches?

commit f0fa91971e35c1df7381ac289ece9bd5f07f8535
Author: Jonathan Wakely <jwak...@redhat.com>
Date:   Tue Aug 31 09:46:41 2021

    c++: Fix docs on assignment of virtual bases [PR60318]
    
    The description of behaviour is incorrect, the virtual base gets
    assigned before entering the bodies of A::operator= and B::operator=,
    not after.
    
    The example is also ill-formed (passing a string literal to char*) and
    undefined (missing return from Base::operator=).
    
    Signed-off-by: Jonathan Wakely <jwak...@redhat.com>
    
    gcc/ChangeLog:
    
            PR c++/60318
            * doc/trouble.texi (Copy Assignment): Fix description of
            behaviour and fix code in example.

diff --git a/gcc/doc/trouble.texi b/gcc/doc/trouble.texi
index 40c51ae21cb..8b34be4aa63 100644
--- a/gcc/doc/trouble.texi
+++ b/gcc/doc/trouble.texi
@@ -865,10 +865,11 @@ objects behave unspecified when being assigned.  For 
example:
 @smallexample
 struct Base@{
   char *name;
-  Base(char *n) : name(strdup(n))@{@}
+  Base(const char *n) : name(strdup(n))@{@}
   Base& operator= (const Base& other)@{
    free (name);
    name = strdup (other.name);
+   return *this;
   @}
 @};
 
@@ -901,8 +902,8 @@ inside @samp{func} in the example).
 G++ implements the ``intuitive'' algorithm for copy-assignment: assign all
 direct bases, then assign all members.  In that algorithm, the virtual
 base subobject can be encountered more than once.  In the example, copying
-proceeds in the following order: @samp{val}, @samp{name} (via
-@code{strdup}), @samp{bval}, and @samp{name} again.
+proceeds in the following order: @samp{name} (via @code{strdup}),
+@samp{val}, @samp{name} again, and @samp{bval}.
 
 If application code relies on copy-assignment, a user-defined
 copy-assignment operator removes any uncertainties.  With such an

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