On 3/7/26 12:15, Richard Biener wrote:


Am 07.03.2026 um 12:09 schrieb Jørgen Kvalsvik <[email protected]>:

The masking table was computed by considering the cartesian product of
incoming edges, ordering the pairs, and doing upwards BFS searches
from the sucessors of the lower topologically index'd ones (higher in
the graph). The problem with this approach is that all the nodes we
find from the higher candidates would also be found from the lower
candidates, and since we want to collect the set intersection, any
higher candidate would be dominated by lower candidates.

We need only consider adjacent elements in the sorted set of
candidates.  This has a dramatic performance impact for large
functions.  The worst case is expressions on the form (x && y && ...)
and (x || y || ...) with up-to 64 elements. I did a wallclock
comparison of the full analysis phase (including emitting the GIMPLE):

test.c:
    int fn (int a[])
    {
      (a[0] && a[1] && ...) // 64 times
      (a[0] && a[1] && ...) // 64 times
      ...                   // 500 times
    }

    int main ()
    {
      int a[64];
      for (int i = 0; i != 10000; ++i)
        {
          for (int k = 0; k != 64; ++k)
            a[k] = i % k;
          fn1 (a);
        }
    }

Without this patch:
    fn1 instrumented in 20822.303 ms (41.645 ms per expression)

With this patch:
    fn1 instrumented in 1288.548  ms (2.577  ms per expression)

Impressive

I also tried considering terms left-to-right and, whenever the search
found an already-processed expression it would stop the search and
just insert its complete table entry, but this had no measurable
impact on compile time, and the result was a slightly more complicated
function.

This inefficiency went unnoticed for a while, because these
expressions aren't very common.  The most I've seen in the wild is 27
conditions, and that involved a lot of nested expressions which aren't
impacted as much.

OK, assuming it bootstraps and tests OK

Richard

It bootstraps and tests on x86-64-linux. I pushed it now.

Thanks,
Jørgen


gcc/ChangeLog:

    * tree-profile.cc (struct conds_ctx): Add edges.
    (topological_src_cmp): New function.
    (masking_vectors): New search strategy.
---
gcc/tree-profile.cc | 44 ++++++++++++++++++++++++++++++++++----------
1 file changed, 34 insertions(+), 10 deletions(-)

diff --git a/gcc/tree-profile.cc b/gcc/tree-profile.cc
index fed218eb60b..7f803814a33 100644
--- a/gcc/tree-profile.cc
+++ b/gcc/tree-profile.cc
@@ -182,6 +182,7 @@ struct conds_ctx
     auto_sbitmap G1;
     auto_sbitmap G2;
     auto_sbitmap G3;
+    auto_vec<edge, 64> edges;

     explicit conds_ctx (unsigned size) noexcept (true) : G1 (size), G2 (size),
     G3 (size)
@@ -217,6 +218,16 @@ topological_cmp (const void *lhs, const void *rhs, void 
*top_index)
     return (*im)[l->index] - (*im)[r->index];
}

+/* topological_cmp of the src block of LHS and RHS.  The TOP_INDEX argument
+   should be the top_index vector from ctx.  */
+int
+topological_src_cmp (const void *lhs, const void *rhs, void *top_index)
+{
+    const_edge l = *(const edge*) lhs;
+    const_edge r = *(const edge*) rhs;
+    return topological_cmp (&l->src, &r->src, top_index);
+}
+
/* Find the index of NEEDLE in BLOCKS; return -1 if not found.  This has two
    uses, sometimes for the index and sometimes for set member checks.  Sets are
    typically very small (number of conditions, >8 is uncommon) so linear search
@@ -437,7 +448,17 @@ condition_uid (struct function *fn, basic_block b)

    We find the terms by marking the outcomes (in this case c, T) and walk the
    predecessors starting at top (in this case b) and masking nodes when both
-   successors are marked.
+   successors are marked.  This is equivalent to removing the two outcome nodes
+   of the subexpression and finding the nodes not in the inverse reachability
+   set.
+
+   We only have to consider the pairs of top, bot where top is the the closest
+   (highest-index'd) candidate that still satisfies top < bot in the
+   topological order, as this will be the immediate left operand.  The nodes of
+   the other left operands will also be found when going through the righmost
+   term, and a lower-index'd top would just find subsets.  This has a
+   significant performance impact, 15-20x faster for the worst cases of (x && y
+   && ..) with no nesting.

    The masking table is represented as two bitfields per term in the expression
    with the index corresponding to the term in the Boolean expression.
@@ -514,16 +535,19 @@ masking_vectors (conds_ctx& ctx, array_slice<basic_block> 
blocks,
     for (size_t i = 1; i != body.length (); i++)
     {
    const basic_block b = body[i];
-    for (edge e1 : b->preds)
-    for (edge e2 : b->preds)
-    {
-        if (e1 == e2)
-        continue;
-        if ((e1->flags | e2->flags) & EDGE_COMPLEX)
-        continue;
+    if (b->preds->length () < 2)
+      continue;
+    ctx.edges.truncate (0);
+    ctx.edges.reserve (b->preds->length ());
+    for (edge e : b->preds)
+      if (!(e->flags & EDGE_COMPLEX))
+        ctx.edges.quick_push (contract_edge_up (e));
+    ctx.edges.sort (topological_src_cmp, &ctx.top_index);

-        edge etop = contract_edge_up (e1);
-        edge ebot = contract_edge_up (e2);
+    for (size_t i0 = 0, i1 = 1; i1 != ctx.edges.length (); ++i0, ++i1)
+    {
+        edge etop = ctx.edges[i0];
+        edge ebot = ctx.edges[i1];
        gcc_assert (etop != ebot);

        const basic_block top = etop->src;
--
2.47.3


Reply via email to