On Wed, Jun 12, 2013 at 04:22:46PM +0100, Tejas Belagod wrote: > From the IR above, it seems that result of widening the high part > (vect__12.6_40) is being stored at offset 0 from _29 and result of > widening the low part goes into *(_29 + 16). Shouldn't this be the > other way around?
Big-endian targets store the high part of multi-byte values at the low address. Why should vectors be different? -- Alan Modra Australia Development Lab, IBM
