On 11/23/2013 08:47 PM, Jason Merrill wrote:
On 11/23/2013 02:21 PM, Mike Stump wrote:
- if (SCALAR_FLOAT_MODE_P (mode))
+#if TARGET_SUPPORTS_WIDE_INT == 0
+ if (!SCALAR_FLOAT_MODE_P (mode))
+ {
+ mem_loc_result->dw_loc_oprnd2.val_class
+ = dw_val_class_const_double;
+ mem_loc_result->dw_loc_oprnd2.v.val_double
+ = rtx_to_double_int (rtl);
+ }
+ else
+#endif
{
unsigned int length = GET_MODE_SIZE (mode);
unsigned char *array
So if the target supports wide ints you'll always use the scalar float
code? Why does that do the right thing?
Jason
if TARGET_SUPPORTS_WIDE_INT != 0, then integers are NEVER placed in
const-doubles. large integers go into CONST_WIDE_INTS so this case
always represents a floating point constant and nothing else. So yes.
I think that you could argue that the comment above this frag needs to
be rewritten because it is wrong if TARGET_SUPPORTS_WIDE_INT != 0.
kenny
