Hi,
On 07/13/2014 06:44 PM, Ulrich Drepper wrote:
But your 4th and 7th call example by itself is not a reason. Again,
the input exclusively determined by the random numbers. Here, of
course, the 4th and 7th use will produce different results. But this
is not what the state of the distribution is supposed to capture. For
that you'll have to save the state of the RNG as well.
Yes, you are right. Saving the full state of the distribution solves
only half of my hypothetical problem, but certainly you have to save it
if you want to, say, reset the RNGs to a common state and get the same
sequences of numbers after the os << x and is >> y pair.
Paolo.