On Jan 26, 2006, Richard Guenther <[EMAIL PROTECTED]> wrote: >> So it is perfectly valid, but if GCC reorders the read from *ip past >> the store to *dp, it turns the valid program into one that misbehaves.
> *ip = 15; ii = *ip; *dp = 1.5; dd = *dp; > Here ^^^ > you are accessing memory of type integer as type double. Yes, but that's not what the Standard defines as undefined. If the stored value is accessed with a type that differs from the effective type, then you lose. But here it's not accessing the stored type; quite the contrary, it's overwriting it, giving the underlying memory a new effective type. Please read 6.5/6-7. -- Alexandre Oliva http://www.lsd.ic.unicamp.br/~oliva/ Red Hat Compiler Engineer [EMAIL PROTECTED], gcc.gnu.org} Free Software Evangelist [EMAIL PROTECTED], gnu.org}
