> On Jan 18, 2014, at 12:04 PM, "Paulo J. Matos" <pa...@matos-sorge.com> wrote:
> 
> On 17/01/14 17:36, Eric Botcazou wrote:
>>> I am not implying that this is a GCC bug, unless you think
>>> WORD_REISTER_OPERATIONS should have avoided the creation of such
>>> paradoxical subreg.
>> 
>> No, that's precisely the contrary, WORD_REGISTER_OPERATIONS tends to create
>> paradoxical subregs.
> 
> I might then, be misunderstanding the reason to enable 
> WORD_REGISTER_OPERATIONS. From the documentation:
> 
> "Macro: WORD_REGISTER_OPERATIONS
> 
>    Define this macro if operations between registers with integral mode 
> smaller than a word are always performed on the entire register. Most RISC 
> machines have this property and most CISC machines do not. "
> 
> The machine I am targeting is a 64bit vector machine. When you perform a 16 
> bit operation, the whole register is changed because the operation actually 
> changes every 16bit group of the register. So it seems I should enable 
> WORD_REGISTER_OPERATIONS.
> 
> As an aside, is there any machine in gcc mainline like this?

Yes spu.  It is a 128bit vector machine, operations happen in that size and 
compares are done in the same size.

I think you misunderstood WORD_REGISTER_OPERATIONS, it means the operation 
happens on the whole register in that a 16bit add is the same as a 32bit one.

Thanks,
Andrew Pinski


> 
>>> What I was looking after was for a generic solution on
>>> my backend that either eliminates the use of paradoxical subregs or forces
>>> reload the transform (subreg:m (reg:n K)), where subreg is paradoxical,
>>> into a zero_extend.
>> 
>> Why would it do that?  That would pessimize for no clear benefit.  Either the
>> paradoxical subreg is correct and there is bug in reload or it is wrong and
>> there is a bug in combine.
> 
> When combine transforms:
> (zero_extend:SI (reg:HI 18))
> into
> (subreg:SI (reg:HI 18))
> it seems then to be doing something wrong. This is because the first 
> explicitly says that bits 0-15 have the value in reg 18 and the bits 16-31 
> are zero. However the second means that bits 0-15 have the value in reg 18 
> and the bits 16-31 may or may not be defined. These are not equivalent I 
> think. So, following your reasoning combine has a bug. Do you agree? If so, I 
> will look for where this transformation is combine is happening.
> 
> 
> -- 
> PMatos
> 

Reply via email to