thanks a lot On 5/18/12, Hammond, Simon David (-EXP) <[email protected]> wrote: > Hi, > > If you know what the clock rate of the processor is the time for a cycle = 1 > / clock rate seconds. If you know a cache access takes 2 cycles then time > for a cache acces = (1 / clock rate) * 2. > > e.g. 1GHz: t_cycle = 1 / 1,000,000,000 seconds > 2 cycle latency = t_cycle * 2 > > Make sure if you change the processor clock you also change the latency > values :). > > ________________________________________ > From: [email protected] [[email protected]] on behalf of > Mahmood Naderan [[email protected]] > Sent: Friday, May 18, 2012 9:19 AM > To: gem5 users mailing list > Subject: [EXTERNAL] [gem5-users] convertig "ns" to "cycles" > > Hi > I papers the latency is mentioned as number of cycles. For example the > latency of L1 cache is said to be 1 or 2 cycles. However in gem5, the > units are based on "seconds". So can we convert "ns" cycles? In > another word, if I want to set the L1 latency to 2 cycles, what is the > corresponding value in "ns"? > > Thanks > -- > // Naderan *Mahmood; > _______________________________________________ > gem5-users mailing list > [email protected] > http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users > > > _______________________________________________ > gem5-users mailing list > [email protected] > http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users >
-- // Naderan *Mahmood; _______________________________________________ gem5-users mailing list [email protected] http://m5sim.org/cgi-bin/mailman/listinfo/gem5-users
