[gem5-users] Map threads onto cores

[Tayebe Sadeghi via gem5-users]

HiExcuse me,i have a problem.At first i use chroot into mounted disk image then 
compile a sample  attached code with g++. In sample code i have a command that 
return number of  existing processor and mapping thread on existing cpu. I 
don't edit fs.py.I use this command  in running gem5 but gem5 show me that 
there is one processor.I don't know why gem5 return one processor whereas I use 
--num-cpu=2???Thanks.
command:./build/X86/gem5.fast configs/example/fs.py 
--kernel=/dist/m5/system1/binaries/x86_64-vmlinux-2.6.22.9.smp 
--disk-image=/dist/m5/system1/disks/linux-x86.img --script=salam.rCS 
--num-cpus=2  --caches --cpu-type=timing

my script.rCS
Description: Binary data

#include <stdio.h>
#include <pthread.h>
#include <unistd.h>

void* DoWork(void* args) {
    printf("ID: %lu, CPU: %d\n", pthread_self(), sched_getcpu());
    return 0;
}

int main() {   

    int numberOfProcessors = sysconf(_SC_NPROCESSORS_ONLN);
    printf("Number of processors: %d\n", numberOfProcessors);

    pthread_t threads[numberOfProcessors];

    pthread_attr_t attr;
    cpu_set_t cpus;
    pthread_attr_init(&attr);

    for (int i = 0; i < numberOfProcessors; i++) {
       CPU_ZERO(&cpus);
       CPU_SET(i, &cpus);
       pthread_attr_setaffinity_np(&attr, sizeof(cpu_set_t), &cpus);
       pthread_create(&threads[i], &attr, DoWork, NULL);
    }
     printf("Number of processors: %d\n", numberOfProcessors);
    for (int i = 0; i < numberOfProcessors; i++) {
        pthread_join(threads[i], NULL);
    }

    return 0;
}

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