> > Concerning performance: I am afraid that the solutions Ken
> came up with were not very optimized for large sequences.
> They have a logarithmic complexity. Let me provide a solution
> that has a linear complexity:
>
> Shouldn't that be exponential...  logarithmic is better than
> linear isn't it?  :)

Yeah, I actually meant complexity roughly matching n * log n (+ some more) for 
Ken's approach versus 2 * n for mine. But it is not entirely fair. My solution 
includes sorting which usually adds a log n as well. I would be interested in 
some measurements, but lack the data to do them myself..

Kind regards,
Geert


drs. G.P.H. (Geert) Josten
Consultant


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