You should be able to quote the text with the colon as a phrase, and then the quote will become a phrase. Something like:
import module namespace search = "http://marklogic.com/appservices/search"; at "/MarkLogic/appservices/search/search.xqy"; search:parse("foo:bar 'foo:bar'", <options xmlns="http://marklogic.com/appservices/search";> <constraint name="foo"> <word> <element ns="http://widgets-r-us.com"; name="name"/> </word> </constraint> <debug>true</debug> </options>) -Danny From: [email protected] [mailto:[email protected]] On Behalf Of Treskon, Matthew Sent: Tuesday, November 06, 2012 2:47 PM To: MarkLogic Developer Discussion Subject: Re: [MarkLogic Dev General] Search term includes colon You may get a better response than this, but you could wildcard it '?' before sending it to search:search. Matthew Treskon From: [email protected]<mailto:[email protected]> [mailto:[email protected]] On Behalf Of Harry B. Sent: Tuesday, November 06, 2012 5:44 PM To: General MarkLogic Developer Discussion Subject: [MarkLogic Dev General] Search term includes colon I am using search:search and the grammar options currently see the colon (:) as the joiner-string for a constraint. The requirement has surfaced where the query string may contain a colon and it will not be meant as a joiner, ex. "Kill Bill:2". What should I do to accommodate this requirement? Encoding the colon doesn't help. It seems perhaps I need to not use the colon as a joiner and use a pipe or some other character? Any other ideas? Thanks, Harry This electronic message contains information generated by the USDA solely for the intended recipients. Any unauthorized interception of this message or the use or disclosure of the information it contains may violate the law and subject the violator to civil or criminal penalties. If you believe you have received this message in error, please notify the sender and delete the email immediately.
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