I think you need to either get rid of the space in "auto, kind" or change
"," to ", " in your call to fn:tokenize(). fn:tokenize("auto, kind", ",")
returns "auto" and " kind" (note leading space), so the second token
matches nothing.
On Mon, Dec 8, 2014 at 1:48 PM, Danny Sokolsky <danny.sokol...@marklogic.com
> wrote:
> You already know how to do that. Just do something like this (passing a
> sequence into a word-query treats each item as an or):
>
> let $s := (fn:tokenize("auto, kind", ","))
> let $doc :=
> <a>
> <b id="car">
> <c xml:lang="en">car</c>
> <c xml:lang="nl">auto</c>
> <c xml:lang="fr">voiture</c>
> </b>
> <b id="house">
> <c xml:lang="en">house</c>
> <c xml:lang="nl">huis</c>
> <c xml:lang="fr">maison</c>
> </b>
> <b id= "child">
> <c xml:lang="en">child</c>
> <c xml:lang="nl">kind</c>
> <c xml:lang="fr">enfant</c>
> </b>
> </a>
> return $doc//c[cts:contains(., cts:word-query($s, "lang=nl") )]
>
> -----Original Message-----
> From: general-boun...@developer.marklogic.com [mailto:
> general-boun...@developer.marklogic.com] On Behalf Of Frank Mortier
> Sent: Monday, December 08, 2014 10:38 AM
> To: MarkLogic Developer Discussion
> Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
> results in inconsistent output
>
> Thanks
>
> Danny, I need to get from the string ('auto, kind') to ('auto', 'kind').
>
> Chris, it should return 'car' and 'child'.
>
> Tim, does not work, returns only the first id 'car'
>
> Rob, same answer as for Danny.
>
>
>
>
> -----Original Message-----
> From: general-boun...@developer.marklogic.com [mailto:
> general-boun...@developer.marklogic.com] On Behalf Of Danny Sokolsky
> Sent: 08 December 2014 19:15
> To: MarkLogic Developer Discussion
> Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
> results in inconsistent output
>
> Hi Frank,
>
> Or how about if you do a language-sensitive search. For example:
>
> let $doc :=
> <a>
> <b id="car">
> <c xml:lang="en">car</c>
> <c xml:lang="nl">auto</c>
> <c xml:lang="fr">voiture</c>
> </b>
> <b id="house">
> <c xml:lang="en">house</c>
> <c xml:lang="nl">huis</c>
> <c xml:lang="fr">maison</c>
> </b>
> <b id= "child">
> <c xml:lang="en">child</c>
> <c xml:lang="nl">kind</c>
> <c xml:lang="fr">enfant</c>
> </b>
> </a>
> return $doc//c[cts:contains(., cts:or-query((
> cts:word-query("auto", "lang=nl"),
> cts:word-query("kind", "lang=nl"))) )] => <c
> xml:lang="nl">auto</c> <c xml:lang="nl">kind</c>
>
> -Danny
>
> -----Original Message-----
> From: general-boun...@developer.marklogic.com [mailto:
> general-boun...@developer.marklogic.com] On Behalf Of Christopher Hamlin
> Sent: Monday, December 08, 2014 10:14 AM
> To: MarkLogic Developer Discussion
> Subject: Re: [MarkLogic Dev General] Marklogic node replace of same node
> results in inconsistent output
>
> Hi Frank,
>
> Not exactly sure if it's what you want, but maybe helps you get closer:
>
> for $x in $doc/b/c[@xml:lang eq"nl"]
> where $x/fn:string() = fn:tokenize('auto, kind', ',')
> return
> $x/../@id/fn:string()
>
> returns 'car'.
>
> I changed it so it compares the string value of $x with a list of strings
> from tokenize. Note that I'm using = instead of eq. That lets you use a
> sequence compare. Also the return now returns the @id attribute node.
>
> - Chris
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