Right -- that expression was for inspecting the arguments.

June Kim was getting a length error with # rather than ;

I had not intended to distract away from that issue.

Thanks

-- 
Raul

On Sat, Oct 22, 2022 at 12:31 PM Henry Rich <[email protected]> wrote:
>
> I get
>
>     (>1 0 1; 1 1 0; 0 1 1 ) ;"_ 1 > 1 2 3;4 5 6
>
> +-----+-----+
> |1 0 1|1 2 3|
> |1 1 0|     |
> |0 1 1|     |
> +-----+-----+
> |1 0 1|4 5 6|
> |1 1 0|     |
> |0 1 1|     |
> +-----+-----+
>
> Henry Rich
>
> On 10/22/2022 12:17 PM, Raul Miller wrote:
> > When I inspect the arguments being applied here
> >
> >     (>1 0 1; 1 1 0; 0 1 1 ) ;"_ 1 > 1 2 3;4 5 6
> >
> > I see no reason for a length error.
> >
>
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