5 5{. 0 0$''




   5 5{.''
|length error
|   5 5    {.''

But this looks like a rank error to me.


On Mon, 20 Feb 2023 at 10:39 PM Raul Miller <[email protected]> wrote:

> Generally speaking, errors of this sort are "heuristic" -- the idea is
> to catch coding issues which were probably mistakes.
>
> Also, in contexts where ($) could produce the same result as ({.), you
> could append a desired fill element $'s right argument.
>
> Or, at least, that's how I understand it.
>
> --
> Raul
>
> On Mon, Feb 20, 2023 at 9:27 AM Jan-Pieter Jacobs
> <[email protected]> wrote:
> >
> > Looking through the implementation of dev/eformat, I found this line
> which
> > puzzled me:
> >
> https://github.com/jsoftware/dev_eformat/blob/4c285152bb27c2bfcb474738ea3b839e4ce96d0d/eformat.ijs#L496
> >
> > There's nothing wrong with that line, or with the fact it triggers an
> > error, but it does indicate that $ raises an error in a situation where
> {.
> > does not, i.e. reshaping an empty array errors, while overtaking from one
> > does not.
> >
> > Indeed, 5 $ '' or 5$ 0$0 give an error, while 5 {. '' and 5 {. 0$0 just
> > work, producing arrays of 5 spaces or zeros as expected. 5 $!.'' '' also
> > works, as does 5$!.1 ''.
> > Why wouldn't $ be able to see the data type (and thereby, fill element)
> of
> > it's y argument, and fill accordingly? As far as I remember, any noun in
> J
> > has a datatype, and a fill element. As the the fill element is a scalar,
> > the dimensionality being different in the case of $ shouldn't matter
> either.
> >
> > Is there anything I'm missing, or is this really an inconsistency without
> > any reason for existence?
> >
> > Best regards,
> > Jan-Pieter
> > ----------------------------------------------------------------------
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> ----------------------------------------------------------------------
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