Why so complicated?

   (i.2 3) ([EMAIL PROTECTED] #: i.&,)  4
1 1

   (i.2 2 3) ([EMAIL PROTECTED] #: i.&,)  4
0 1 1


--- Dan Bron <[EMAIL PROTECTED]> wrote:

> Terrence:
> 
> Bill's right.  It's not clear what output you desire.  That's why his result 
> is:
> 
> >     (i. 2 3) i."1[4
> >  3 1
> 
> But Devon's is:
> 
> >     (i. 2 3) ixmd 4
> >  1 1
> 
> Both are correct, but they're answering different questions.  Here's another 
> possible answer:
> 
>          4 = i. 2 3
>       0 0 0
>       0 1 0
> 
> Which leads directly to other formulations of Devon's  ixmd  :
> 
>          idx0 =. $ #: I.@:,
>          idx1 =. 4 $. $. 
>       
>          imx0 =: idx0@:=
>          imx1 =: idx1@:=
>       
>          4 imx0 i. 2 3
>       1 1
>          4 imx1 i. 2 3
>       1 1
> 
> Which can be extended to seeking any rectangle (cuboid)  x  in array  y  :
> 
> 
>          ptrn =. E.&>/@:((>. - ,)&:(#@:$) ,:@:]^:[&.> ,&:<)
>       
>          4 idx0@:ptrn i. 2 3
>       1 1
>          
> 
> -Dan
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
> 


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