In APL, before or after the introduction of squish-quad indexing,
a scalar is an array.   



----- Original Message -----
From: Ian Shannon <[email protected]>
Date: Monday, October 25, 2010 20:00
Subject: Re: [Jgeneral] "J In A Day" --crits please
To: General forum <[email protected]>

> Roger,
> 
> To supplement/replace bracket [; ; ] index notation in APL, IBM 
> introduced the index function (squid I think it is called) in 
> APL2 which can index a scalar as well as arrays that bracket 
> indexing can. Bracket index cannot index a scalar,
> 
> Hence stating that "parts of an array may be selected by bracket 
> indexing" either needs a note that this does not include arrays 
> of rank zero, or in VSAPL scalars are not considered arrays.
> 
> I submit that, with the introduction of squid, scalars were made 
> first class citizens in IBMs APL and confirmed a place as an 
> array capable of being indexed like other arrays. Up until then 
> scalars were (one could argue) not arrays.
> 
> BTW.  In describing APL and J to others one of the first 
> "novel" features of the languages I talk about is that data 
> items in the languages are "array of any rank" and the plain 
> numbers that they would expect to be data items in a computer 
> language are just "arrays of rank 0".
> 
> Ian
> 
> 
> Ian Shannon
> Landscape Modelling and Decision Support Section
> Department of Environment, Climate Change & Water (NSW)
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> 
> 
> -----Original Message-----
> From: [email protected] [mailto:general-
> [email protected]] On Behalf Of Roger Hui
> Sent: Tuesday, 26 October 2010 12:19 PM
> To: General forum
> Subject: Re: [Jgeneral] "J In A Day" --crits please
> 
> I had/have been an APLer for many years and I have
> never heard of scalars not being arrays.  As far as
> I know 99 is not just now deemed an array but
> have always been deemed an array.  I'd be interested 
> in any APL reference you can find that says otherwise.
> 
> A more ancient reference for that fact that a scalar is an 
> array.  
> Falkoff and Iverson, The APL\360 Terminal System, 1967-10-16.
> http://www.jsoftware.com/papers/APL360TerminalSystem.htm
> 
> - A vector has a "rank" of one, the term being used, 
> as in tensor analysis, to mean the number of indices 
> required to identify a single element in an array. 
> Hence, a scalar has rank zero and a matrix has rank two.
> 
> - No special notational convention is required for the 
> element-by-element extension, so that in the expression a+b , 
> for example, a and b may be any pair of matching arrays. 
> If one argument is a scalar the other may be any array, ...
> 
> ---
> 
> In any case, you have not addressed the practical point
> I raised:  if a scalar is not an array, you are going to
> need a term for "array or scalar".  Another way to 
> look at it is, why is it useful to distinguish between
> an array and a scalar?
> 
> Whether a scalar is an array is not a statement that
> you can prove one way or the other, and you have to
> decide on considerations in the preceding paragraph,
> or considerations similar to same.
> 
> Finally, why is it counter-intuitive that a scalar is
> an array?
> 
> 
> 
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