Excerpts from Mike Frysinger's message of Wed Oct 13 20:51:35 +0200 2010:
> path_exists() {
> local opt=$1
> [[ ${opt} == -[ao] ]] && shift || opt="-a"
>
> # no paths -> return false
> # same behavior as: [[ -e "" ]]
> [[ $# -eq 0 ]] && return 1
>
> local p r=0
> for p in "$@" ; do
> [[ -e ${p} ]]
> : $(( r += $? ))
> done
1) Why check every path in both "and" and "or" cases?
2) Even simpler:
for p; do
[[ -e $p ]]
((r+=$?))
done
>
> case ${opt} in
> -a) return $(( r != 0 )) ;;
> -o) return $(( r == $# )) ;;
> esac
> }
--
Amadeusz Żołnowski
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