Hi,
I used the "IP Address Converter" section.
I got the binary for the first IP (218.144.0.0), which is: 11011010 10010000 00000000 00000000
Then for the second (218.159.255.255), which is 11011010 10011111 11111111 11111111
Notice how the first 12 bits stay the same, and the last 12 change? 12 is the magic number in this case. :-)
There should be an easier tool for this, but it does the trick.
Chris
Ralph Slooten wrote:
Wow, thanks Chris for the link .... I just asked my boss to explain it to me (without showing him your answer) and he manually worked it out to be exactly the same. The issue I have is binary etc ... it's still greek to me (I will try learn it soon though).
Ok, now for the real n00b question :-) In which section did you work it out on that page (possibly a screenshot sent to my email if explaining is hard)?
Thanks for the help,
Greetings Ralph
Chris Boot wrote:
Hi,
I found a nice IP address calculator at http://www.telusplanet.net/public/sparkman/netcalc.htm
Using that, we get 218.144.0.0/12.
HTH, Chris
Ralph Slooten wrote:
Hello fellow gentoo users,
I run my own dedicated internet server from home with of course gentoo. What I have noticed, as probably many of you have, is that users from certain ISP's do daily attempts to relay mail, log into ssh etc etc ... Ok, so I'm pretty well secured as they don't even come close, but I'm still not happy.
Most of these attempts come from kornet, as with most of my spam. What I would like to do is drop their whole entire ip-range with iptables... but how? I know how with a simple subnet, but some (they have several) of their ranges are given as:
218.144.0.0 - 218.159.255.255
Is there any way to add this range in iptables easily, without having to do each from 218.144* 218.145* etc etc ....
Greetings Ralph
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