Myname is Andra Ureche and I am studying in Austria my Master in
AerospaceEngineering.Currently I am doing my thesis together with Schiebel in
finding aflight test area in Austria.Ihave created a code in Matlab which is
searching this area in a data file whichcovers Austria and it is in Lambert
EPSG 31287 coordinate system (N,E, andelevation). The next step is export the
solutions from Matlab (polygons definedby 4 points) into a .kml file for
visualization in Google Earth. Here theproblem arrived… I need to convert my
solutions to WGS84. Ihave made this Matlab file to convert one point from
Lambert to WGS84 but I ammissing 3 degrees and I am not sure what is done
wrong. I have attached thefile to this email. Canyou please help me with this
conversion? Thankyou in advance. Kindregards, Andra Ureche
a=6378137.0;
f=1/298.257223563;
e=sqrt(2*f-f^2);
phiF=(47+30/60)*(pi/180);
lambdaF=(13+20/60)*(pi/180);
phi1=49*(pi/180);
phi2=46*(pi/180);
Ef=400000;
Nf=400000;
E=576892.512074;
N=292949.267204;
%phi=0.49741884;
%lambda=-1.67551608;
m1=cos(phi1)/(1-e^2*(sin(phi1))^2)^0.5;
m2=cos(phi2)/(1-e^2*(sin(phi2))^2)^0.5;
%t=(tan((pi/4)-(phi/2))/((1-e*sin(phi))/(1+e*sin(phi)))^(e/2));
tF=(tan((pi/4)-(phiF/2))/((1-e*sin(phiF))/(1+e*sin(phiF)))^(e/2));
t1=(tan((pi/4)-(phi1/2))/((1-e*sin(phi1))/(1+e*sin(phi1)))^(e/2));
t2=(tan((pi/4)-(phi2/2))/((1-e*sin(phi2))/(1+e*sin(phi2)))^(e/2));
n=(log(m1)-log(m2))/(log(t1)-log(t2));
F=m1/(n*(t1^n));
%r=a*F*(t^n);
rF=a*F*(tF^n);
%theta=n*(lambda-lambdaF);
%E=Ef+r*sin(theta);
%N=Nf+rF-r*cos(theta);
rprim=((E-Ef)^2+(rF-(N-Nf))^2)^0.5;
tprim=(rprim/(a*F))^(1/n);
thetaprim=atan((E-Ef)/(rF-(N-Nf)));
phi_initial=(pi/2-2*atan(tprim))*(180/pi);
phi_2iteration=(pi/2-2*atan(tprim*((1-e*sin(phi_initial)/(1+e*sin(phi_initial)))^(e/2))))*(180/pi);
phi_3iteration=(pi/2-2*atan(tprim*((1-e*sin(phi_2iteration)/(1+e*sin(phi_2iteration)))^(e/2))))*(180/pi);
phi_4iter=(pi/2-2*atan(tprim*((1-e*sin(phi_3iteration)/(1+e*sin(phi_3iteration)))^(e/2))))*(180/pi);
lamba_initial=((thetaprim/n)+lambdaF)*(180/pi);
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