Hi Sushil,
From the path you can get to the individual edges. Each edge contains a
"data" object, which is the original linestring.
eg.
Path p = ...
for (Iterator itr = p.getEdges().iterator(); itr.hasNext();) {
Edge e = (Edge)itr.next();
LineString line = (LineString)e.getObject();
}
As for displaying, you could display the path as the collection of
seperate linestrings, but most of the time I have found it useful to
join the linestrings into a single contigous one. There is some utility
code that can do this in
org.geotools.graph.util.GeometryUtil#joinLineStrings.
After you have the single geometry, not sure what the best way to
display it is. I have found that writing the paths to a seperate
shapefile and styling it appropriatly works nicley.
Any more questions just let me know.
-Justin
[EMAIL PROTECTED] wrote:
hi Justin
thanks for ur prompt reply..
below m including th code that i m using...
URL ur1
=MapViewer.class.getClassLoader().getResource("geotool_routing/road_nw.shp");
final DataStore store1 = new ShapefileDataStore(ur1);
FeatureType ft1 = store1.getSchema("road_nw");
final FeatureSource features =
store1.getFeatureSource("road_nw");
LineStringGraphGenerator lgb = new LineStringGraphGenerator();
FeatureResults fsShape = features.getFeatures();
FeatureCollection fc = fsShape.collection();
FeatureIterator feat = fc.features();
//System.out.println("feats===="+feat);
Envelope envelope = fc.getBounds();
while (feat.hasNext())
{
Feature ft = feat.next();
System.out.println("inside====");
if (envelope.contains(ft.getBounds()))
{
//System.out.println("Road ID:"+
ft.getAttribute("Id").toString().trim() + "\tAtribute:"
+ft.getAttribute(0));
lgb.add(ft.getAttribute(0));
}
System.out.println("outside====");
}
Graph g = lgb.getGraph();
Node src1 = lgb.getNode(new Coordinate(3.20469314429218,
712.8185448235371));
Node dest1 = lgb.getNode(new Coordinate(-9.732497499755635,
308.15158580176615));
DijkstraIterator.EdgeWeighter weighter = new
DijkstraIterator.EdgeWeighter()
{
public double getWeight(Edge e)
{System.out.println("soni soni");
//LineSegment line = (LineSegment)e.getObject();
LineString line = (LineString)e.getObject();
System.out.println("length==="+line.getLength());
return(line.getLength());
}
};
DijkstraShortestPathFinder dsp = new DijkstraShortestPathFinder(g, src1,
weighter);
System.out.println("Calculating Paths....");
dsp.calculate();
Path p = dsp.getPath(dest1);
here i m getting the path as
path==[1, 0, 4, 3]
i want it to display this path dynamically on GUI with diffrent colour on
original shape file..
Thanks and Regards
Sushil Kumar Soni
Tata Consultancy Services Limited
Mailto: [EMAIL PROTECTED]
Website: http://www.tcs.com
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--
Justin Deoliveira
The Open Planning Project
http://topp.openplans.org
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