Thanks Rafael,

Ken had recommended :-

EF1.Text.Left(5) which works great.
Another method (like yours) is always good to have.

Thanks again.

Lennox.

Rafael Vallejo <[EMAIL PROTECTED]> wrote: Dim A as String
A=mid(EF1.text,1,4)

A gets the value you asked for


Lennox Jacob escribi�:

>Hello,
>How do I get my app to read the first 5 characters in editfield, EF1?
>Thanks.
>Lennox
>
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