Thanks Norman and Jose. So I guess I need to write a little method to strip the quotes off by finding out the ascii for double quotes? Or maybe something like this... (Is there separate ascii for left quotes and right quotes?)
dim i as integer dim s, t as string t = "Jones, Jim" s = "" for i = 1 to len(t) c = mid(t, i) if c <>""" and c <> """ then s = s + c next _______________________________________________ Unsubscribe or switch delivery mode: <http://www.realsoftware.com/support/listmanager/> Search the archives of this list here: <http://support.realsoftware.com/listarchives/lists.html>
