Without looking into the precise details, this looks dangerous to me. Why do you want this? The danger I see lurking is that you might find two RdrNames that give the same answer to getUnique but represent different things:
foo x = x + (\x -> x) 3 I see two `x`s there that will have the same Unique attached to their RdrNames but will be very different. In fact, I'm surprised that OccName has a Uniquable instance, which seems similarly dangerous to me. Richard On Jun 16, 2014, at 7:45 AM, Jan Stolarek <jan.stola...@p.lodz.pl> wrote: > Hi all, > > I just found myself in the need of Uniquable instance for RdrName. I'm > surprised that such > instance does not exist already because other datatypes like Name or OccName > already have > Uniquable instances. So, is there a reason why Uniquable instance for RdrName > does not exist > already (other than "it wasn't needed")? How should such an instance look > like? I made an > attempt: > > rdrNameUnique :: RdrName -> Unique > rdrNameUnique (Unqual occName) = getUnique occName > rdrNameUnique (Qual _ occName) = getUnique occName > rdrNameUnique (Orig _ occName) = getUnique occName > rdrNameUnique (Exact name ) = getUnique name > > But I suspect this might be wrong: > - cases 1 and 4 simply return a Unique for the OccName/Name stored inside > RdrName. I think this > will assign the same Unique to RdrName and corresponding OccName/Name. Is > this allowed? > - cases 2 and 3 ignore the Module stored inside RdrName. Again, this assigns > the RdrName with a > Unique identical to OccNames stored inside it. > > Help appreciated. > > Janek > _______________________________________________ > ghc-devs mailing list > ghc-devs@haskell.org > http://www.haskell.org/mailman/listinfo/ghc-devs _______________________________________________ ghc-devs mailing list ghc-devs@haskell.org http://www.haskell.org/mailman/listinfo/ghc-devs