On Tue, 19 Apr 2005, David Meybohm wrote:
But doesn't this require assuming the distribution of MD5 is uniform, and don't the papers finding collisions in less show it's not? So, your birthday-argument for calculating the probability wouldn't apply, because it rests on the assumption MD5 is uniform, and it isn't.
No, the collision papers don't show this at all.
--scott
atomic strategic HBDRILL SARANAC COBRA JUDY Ft. Meade assassination politics Mossad HOPEFUL ZPSEMANTIC DTFROGS HTKEEPER LITEMPO LIONIZER operation
( http://cscott.net/ )
-
To unsubscribe from this list: send the line "unsubscribe git" in
the body of a message to [EMAIL PROTECTED]
More majordomo info at http://vger.kernel.org/majordomo-info.html
