Junio C Hamano <gits...@pobox.com> writes:

> +     while (url_len && pat_len) {
> +             const char *url_next = end_of_token(url, '.', url_len);
> +             const char *pat_next = end_of_token(pat, '.', pat_len);
> + ...
>       }
>  
> +     return 1;

Embarrassing.  The last one must be "have they both run out?" i.e.

        return (!url_len && !pat_len);

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