On Tue, May 8, 2018 at 12:59 AM, Stefan Beller <sbel...@google.com> wrote:
> @@ -501,9 +509,31 @@ void raw_object_store_clear(struct raw_object_store *o)
> void parsed_object_pool_clear(struct parsed_object_pool *o)
> {
> /*
> - * TOOD free objects in o->obj_hash.
> - *
> * As objects are allocated in slabs (see alloc.c), we do
> * not need to free each object, but each slab instead.
> + *
> + * Before doing so, we need to free any additional memory
> + * the objects may hold.
> */
> + unsigned i;
> +
> + for (i = 0; i < o->obj_hash_size; i++) {
> + struct object *obj = o->obj_hash[i];
> +
> + if (!obj)
> + continue;
> +
> + if (obj->type == OBJ_TREE) {
> + free(((struct tree*)obj)->buffer);
It would be nicer to keep this in separate functions, e.g.
release_tree_node() and release_commit_node() to go with
alloc_xxx_node().
> + } else if (obj->type == OBJ_COMMIT) {
> + free_commit_list(((struct commit*)obj)->parents);
> + free(&((struct commit*)obj)->util);
> + }
> + }
I still don't see who frees obj_hash[] (or at least clears it if not
freed). If I'm going to use this to free memory in pack-objects then
I'd really prefer obj_hash[] freed because it's a big _big_ array.
Just to be clear, what I mean is
FREE_AND_NULL(o->obj_hash);
o->obj_hash_size = 0;
> +
> + clear_alloc_state(o->blob_state);
> + clear_alloc_state(o->tree_state);
> + clear_alloc_state(o->commit_state);
> + clear_alloc_state(o->tag_state);
> + clear_alloc_state(o->object_state);
> }
--
Duy
