Convert 'match_explicit_refs()' to take a 'struct refspec' as a
parameter instead of a list of 'struct refspec_item'.

Signed-off-by: Brandon Williams <bmw...@google.com>
---
 remote.c | 9 ++++-----
 1 file changed, 4 insertions(+), 5 deletions(-)

diff --git a/remote.c b/remote.c
index 9eb79ea19..84dda3fd0 100644
--- a/remote.c
+++ b/remote.c
@@ -1073,12 +1073,11 @@ static int match_explicit(struct ref *src, struct ref 
*dst,
 }
 
 static int match_explicit_refs(struct ref *src, struct ref *dst,
-                              struct ref ***dst_tail, struct refspec_item *rs,
-                              int rs_nr)
+                              struct ref ***dst_tail, struct refspec *rs)
 {
        int i, errs;
-       for (i = errs = 0; i < rs_nr; i++)
-               errs += match_explicit(src, dst, dst_tail, &rs[i]);
+       for (i = errs = 0; i < rs->nr; i++)
+               errs += match_explicit(src, dst, dst_tail, &rs->items[i]);
        return errs;
 }
 
@@ -1302,7 +1301,7 @@ int match_push_refs(struct ref *src, struct ref **dst,
                refspec = default_refspec;
        }
        refspec_appendn(&rs, refspec, nr_refspec);
-       errs = match_explicit_refs(src, *dst, &dst_tail, rs.items, rs.nr);
+       errs = match_explicit_refs(src, *dst, &dst_tail, &rs);
 
        /* pick the remainder */
        for (ref = src; ref; ref = ref->next) {
-- 
2.17.0.441.gb46fe60e1d-goog

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