On Wed, Jan 29, 2014 at 09:52:45PM +0100, David Kastrup wrote: > Junio C Hamano <gits...@pobox.com> writes: > > Hmm... if you were to implement a set of pointers in such a way that > > you can cheaply tell if an unknown pointer belongs to that set, you > > would use a hashtable, keyed with something that is derived from the > > value of the pointer casted to uintptr_t, I would think. > > The types intptr_t and uintptr_t are optional in ISO/IEC 9899:1999 > (C99). So it would seem that I'd be covering fewer cases rather than > more in that manner.
I think we already use uintptr_t in the codebase, and if it's not
present, we typedef it to unsigned long. So I think it should be fine
(and well-defined) if instead of doing
void *p, *q;
...
if (p < q)
...
you do:
void *p, *q;
...
if ((uintptr_t)p < (uintptr_t)q)
...
Then on those systems where the compiler has some bizarre undefined
behavior checking, the code will work. On systems that don't have
uintptr_t, the compiler is probably not smart enough to perform such a
check anyway.
--
brian m. carlson / brian with sandals: Houston, Texas, US
+1 832 623 2791 | http://www.crustytoothpaste.net/~bmc | My opinion only
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