Sun, 23 Sep 2001 02:04:49 -0700, Ashley Yakeley <[EMAIL PROTECTED]> pisze:
> I would assume that Ptr types would always be mapped to non-const
> pointers.
It would be impossible then to directly call a C function with a
parameter declared as a const pointer. It's illegal in C to have
mismatching prototypes of the same function.
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- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Marcin 'Qrczak' Kowalczyk
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Marcin 'Qrczak' Kowalczyk
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Manuel M. T. Chakravarty
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
- Re: Ptr and ForeignPtr Questions Ashley Yakeley
