John Goerzen writes: > Assuming it is based on wait() or one of its derivatives, > and I suspect it is, you cannot call it more than once > for a single process.
That's what I _assume_, too, but a definite answer would be nice. In the meanwhile, I have found out that it might not be safe to call it once, even: CaughtException waitForProcess: does not exist (No child processes) That's a child I _did_ start and which apparently terminated before I called waitForProcess. Shouldn't I be getting the exit code of that process rather than an exception? Do waitForProcess and getProcessExitCode differ in their behavior other than that one blocks and other doesn't? Peter _______________________________________________ Glasgow-haskell-users mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
