Who can advise, please, is this for sure that the program
\ x -> [f y | y <- g x] is not more expensive in computation than \ x -> let ys = g x in [f y | y <- ys] ? May the difference depend on Haskell implementation? (I suspect that compilers convert one of these programs to another). Thank you in advance for explanation. ----------------- Serge Mechveliani [EMAIL PROTECTED] _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
