Hello, Why is the following a syntax error:
f (view1 -> view2 -> pattern) = ... and the following isn't: f (view1 -> (view2 -> pattern)) = ... I would prefer the first version. regards, Bas _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users
