On January 8, 2012 23:49:47 wren ng thornton wrote: > An alternative is to distinguish, say, (# x #) and its spaceful > constructor (# #) from the spaceless (##); and analogously for the boxed > tuples, though that introduces confusion about parentheses for boxing vs > parentheses for grouping.
I think that sounds pretty good. Here is another that occured to me today (#), (# a #), (# a, b #), (# a, b, c #) ... If you replace the internal ',' with '#' (#), (# a #), (# a # b #), (# a # b # c #), ... you have number of elements = number of '#' - 1. Cheers! -Tyson _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users