I found little bug,
imposible to use '0' as condition parameter
following template don't work
##IFticket.numberoftasks=0## --- ##ENDIFticket.numberoftasks##
##ELSEticket.numberoftasks## ##lang.ticket.numberoftasks## :
##ticket.numberoftasks## ##ENDELSEticket.numberoftasks##
problem with
if (empty($out[2][$key]) ){ // No = : check if ot empty or not null
zero also interpretete as empty, so we need to check length too, or
something similar
if (empty($out[2][$key]) && !strlen($out[2][$key]) ){ // No = : check if ot
empty or not null
2011/2/10 Nicolas Michaux <nicolas-glpi-...@michaux.homelinux.org>
> On Thursday 10 February 2011 10:11:05 Denis Linvinus wrote:
> > Hello!
> Hi,
>
> > > > As we have problem only with template condition, better decode
> > > > only condition.
> > >
> > > Ok, what about this patch for you?
> >
> > This patch also works for me.
> Great news!
>
> > But i don't understand why
> >
> > if (preg_match_all("/##IF([a-z\.]*)[=]?(.*)##/Ui",$string,$out)) {
> >
> > not the same as
> >
> > if (preg_match_all("/##IF([a-z\.]*)[=]?(.*?)##/i",$string,$out)) {
> Maybe we should double the question mark if the whole expression is
> considered ungreedy :
> if (preg_match_all("/##IF([a-z\.]*)[=]??(.*)##/Ui",$string,$out)) {
>
> "The question mark ? changes the behavior of the quantifiers *, +, ? from
> "greedy" to "ungreedy" in a "greedy" regular expression. But the same
> question mark ? changes the behavior of the quantifiers *, +, ? from
> "ungreedy"
> to "greedy" in an "ungreedy" regular expression!"
>
> I didn't test it.
>
> Nicolas
>
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