Hi,
I have a file that contains the redirected output of a big "find"
command. I want to learn how to quickly scan this file for unique
file names, and while I could write a lengthy Perl one-liner, I was
wondering if it could be done more simply with awk. But since I
have never used awk, I was hoping someone could show me The Way.
What I want to do is pretty simple -- awk the file such that the
only output is the contents after the last slash (everything after
that is a file name). One way I wonder if it could be done:
$ awk '/\/([^/]+)$/{print $1}' findoutput.txt
Of course, awk doesn't treat $1 as the captured text from a regex,
as Perl does, so this doesn't really work -- it prints out the
whole first field of any records that match. The net effect of
this is the same as if I had simply done `cat findoutput.txt`.
Can text be captured from an awk regex?
If not, the other alternative I was thinking of was the awk
equivalent of
1. set the field separator to a slash
2. awk the file for the last field.
I've figured out how to set the field separator (from the man page)
but it seems I need to use a numeric variable to represent the
field I want to print. I don't know of a way to get the last field
for any given record/line since one one line it could be $5 and on
another it might be $7, for example.
I'm using awk, not gawk, on a Solaris box. Thanks for any insight.
Erik
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