-------- Original-Nachricht --------
> Datum: Mon, 30 Apr 2012 14:30:37 +0200
> Von: Jean Brefort <[email protected]>
> An: [email protected]
> CC: [email protected]
> Betreff: Re: Gnumeric Python: get position of the current selected cell
> It is not possible in 1.10 but might be in next version if somebody
> helps with porting the Python plugins to using introspection.
>
> Regards,
> Jean
>
Ah ok, thanks for the reply.
I have a partial solution (this is a rather ugly thing, because I almost don't
know anything about gnumeric internals). It took really long time to geht that
running! ;)
The drawback is, it uses always only the first sheet.
So it works in following manner:
it should always copy the entered text of the cell above into the current cell.
I have patched /gnumeric-1.10.17/plugins/python-loader/py-gnumeric.c:
...
py_sheet_cell_active_pos_method (py_Sheet_object *self, PyObject *args);
static PyObject *
...
{(char *) "cell_active_pos",
(PyCFunction) py_sheet_cell_active_pos_method, METH_VARARGS},
...
#include "sheet-view.h"
static PyObject *
py_sheet_cell_active_pos_method (py_Sheet_object *self, PyObject *args)
{
GnmCellPos cell_pos;
GPtrArray *views = self->sheet->sheet_views;
SheetView *view = g_ptr_array_index (views, 0); // 0?????
cell_pos = view->edit_pos;
return py_new_CellPos_object (&cell_pos);
}
and my py file looks like: (only that function):
def f_fill(gui):
wb = gui.get_workbook()
s=wb.sheets()[0]
z=s.cell_active_pos()
tup = z.get_tuple()
if tup[1] == 0:
print "this is the upper cell, no cell above"
return #there is no value up there
c = s.cell_fetch(tup[0], tup[1]-1)
entered_text = c.get_entered_text()
s[tup[0],tup[1]].set_text(entered_text)
If I bind it to a shortcut key, it is rather efficient.
Is there any way to bind a function permanently to a shortcut?
Do you have any hint, how to get the "active" (the currently selected sheet)?
and have the function everywhere?
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