Oskar L. wrote: > So if we start with Bob, we need to have 253 more people, to be able to > make 253 different pairs of which Bob is part of.
We need 22 more people. In a room of 23 people, there are C(23, 2) different pairs, or 253. You should probably refresh your knowledge of combinatorics before talking about the birthday paradox. _______________________________________________ Gnupg-users mailing list Gnupg-users@gnupg.org http://lists.gnupg.org/mailman/listinfo/gnupg-users
