Hi,
Both t2.f() and t2.T1.f() call the same method.
t2.f() calls t2.T1.f() (struct embedding). Inside T1.f(), value of a is 3.
t2.T1.f() calls directly.
Yes, this is reasonable.
If you want absolutely clear to thing to happen, then try this
package main
import "fmt"
func main() {
var t2 T2
t2.a = 5
t2.T1.a = 3
t2.f()
t2.T1.f()
}
type T1 struct {
a int
}
func (t T1) f() {
fmt.Println("T1: ", t.a)
}
type T2 struct {
T1
a int
}
func (t T2) f() {
fmt.Println("T2: ", t.a)
}
On 9/7/2016 16:56, T L wrote:
package main
import "fmt"
func main() {
var t2 T2
t2.a = 5
t2.T1.a = 3
t2.f() // 3
t2.T1.f() // 3
}
type T1 struct {
a int
}
func (t T1) f() {
fmt.Println(t.a)
}
type T2 struct {
T1
a int
}
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http://asit-dhal.github.io/
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