On Fri, Sep 23, 2016 at 10:00 AM, <ishantagarwal1...@gmail.com> wrote:
> Considering what is mentioned in the video, it looks like whenever a second
> has gone by and a message is not returned only then the exit from loop will
> happen.
> Which means the loop may run indefinitely as well if boring function keeps
> on returning something or the other within a second on the channel returned
> by it..
Yes, you're correct, if that's not the desired behavior this should be written:
> t := time.After(1 * time.Second)
> for {
> select {
> case s := <-c:
> fmt.Println(s)
> case <-t:
> fmt.Println("You're too slow.")
> return
> }
> }
—Sam
--
Sam Whited
pub 4096R/54083AE104EA7AD3
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