Am Dienstag, 1. November 2016 02:07:49 UTC+1 schrieb wwa...@gmail.com:
>
> Hello all,
>
> I'm new to Go, and I have a question about identifying types as they're
> encountered in traversing a map[string]interface{}.
>
> I've ended up with a big sieve of type assertions something like this:
>
> if mt.Mi, ok = m.(map[string]int); ok {
> nval, ok = mt.Mi[mk]
> } else if mt.MI, ok = m.(map[string]interface{}); ok {
> nval, ok = mt.MI[mk]
> } else if mt.Mai, ok = m.(map[string][]int); ok {
> nval, ok = mt.Mai[mk]
> } else if mt.Mas, ok = m.(map[string][]string); ok {
> nval, ok = mt.Mas[mk]
> } else if mt.Mmm, ok = m.(map[string]map[string]interface{}); ok {
> nval, ok = mt.Mmm[mk]
>
> mt here is a struct that performs no work; it just associates a type to a
> name, so that the run-time can see the types of the left and the right
> sides of the assignment and determine if an assignment is possible. I
> really hate looking at that statement, but all my attempts at using
> reflection have failed as the compiler can't allocate with all the possible
> types that could be returned, even though in my application I only want to
> allocate for these five types. So that's my question: Can I DRY this up?
>
The code you showed is basically a noop: If this is going to compile
than nval must be of type interface {} and you could replace all this
with a simple
nval = m
You either did not show the last else-block or something is strange here.
V.
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