pasting code for convenience
func main() {
// create backing array
arr := [5]int {0,1,2,3,4}
fmt.Println(arr)
// take a slice of backing array
s1 := arr[:3]
fmt.Println(s1)
fmt.Println(arr)
fmt.Println(cap(s1))
// append to slice, replaces backing array?
s1 = append(s1, 7)
fmt.Println(s1)
fmt.Println(arr)
// append to slice, doesn't replace backing array?
// whats backing the slice?
s1 = append(s1,8,9,10)
fmt.Println(s1)
fmt.Println(arr)
fmt.Println(cap(s1))
}
On Sunday, March 12, 2017 at 11:49:33 AM UTC-7, st ov wrote:
>
> What happens when appending to a slice exceeds the backing capacity?
>
> https://play.golang.org/p/mVezWL4Cbe
>
> In the example given, appending within capacity on line 20 modifies the
> backing array at the successive index.
> But on line 26, when appending exceeds the capacity, the backing array is
> no longer modified. So where are those additional elements stored?
>
> Also the capacity for this new backing store is 12, this is to amortize
> performance correct?
>
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