On Wed, May 3, 2017 at 7:04 PM, T L <tapir....@gmail.com> wrote:
>
>
> On Thursday, May 4, 2017 at 12:46:47 AM UTC+8, Axel Wagner wrote:
>>
>> but
>> const (
>> a = iota
>> b
>> s string
>> d
>> )
>> is not a valid declaration. You can't say "the rule is the same for
>> constants".
>>
>
> For the same rule, I mean just copying the corresponding part from last
> line.
> Yes, declared constant must be assigned. This is an unrelated rule for
> this topic.
>
No, it is not an unrelated rule. Because it means that "just like for
consts" isn't an argument. You need, at the very least, answer the valid
question ("what happens with that var-declaration and why?") raised about
your proposal. Or better yet, realize that var and const declarations
behave very differently and thus "consistency" isn't an argument to add
something otherwise useless.
>
>
>>
>> Again: const-declarations and variable declarations are very different.
>> You can not argue "it's the same"; it's not.
>>
>> On Wed, May 3, 2017 at 6:28 PM, T L <tapi...@gmail.com> wrote:
>>
>>>
>>>
>>> On Thursday, May 4, 2017 at 12:17:13 AM UTC+8, Jan Mercl wrote:
>>>>
>>>> On Wed, May 3, 2017 at 6:00 PM T L <tapi...@gmail.com> wrote:
>>>>
>>>> > Just like what expected for constants.
>>>>
>>>> For constants it's expected to reuse the last iota expression when
>>>> absent. Do you propose that
>>>>
>>>> var (
>>>> a = iota
>>>> b
>>>> )
>>>>
>>>> will become valid and initialize a to 0 and b to 1?
>>>>
>>>> If so, is it valid and what shall happen when one writes
>>>>
>>>> var (
>>>> a = iota
>>>> b
>>>> s string
>>>> d
>>>> )
>>>>
>>>> ?
>>>>
>>>
>>> The rule is same for constants: d is also string, as s.
>>>
>>>
>>>
>>>>
>>>> If it's not valid, why?
>>>>
>>>>
>>>> --
>>>>
>>>> -j
>>>>
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>>
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