Thanks a lot, I also want to know what the first lock meaning is?
在 2018年3月13日星期二 UTC+8下午9:32:35，Burak Serdar写道：
>
> The second lock waits until f() runs and unlocks the mutex.
>
> On Tue, Mar 13, 2018 at 3:37 AM, 郎凯 <langk...@gmail.com <javascript:>>
> wrote:
> > var l sync.Mutex
> > var a string
> >
> > func f() {
> > a = "hello, world"
> > l.Unlock()
> > }
> >
> > func main() {
> > l.Lock()
> > go f()
> > l.Lock()
> > print(a)
> > }
> >
> > I'm a new gopher, reading a blog about lock and having a problem, in
> general
> > , we use sync.Mutex in pairs, in the above code why could it call lock
> two
> > times in main.
> > Any help is Appreciated.
> > Thanks in advanced.
> >
> > --
> > You received this message because you are subscribed to the Google
> Groups
> > "golang-nuts" group.
> > To unsubscribe from this group and stop receiving emails from it, send
> an
> > email to golang-nuts...@googlegroups.com <javascript:>.
> > For more options, visit https://groups.google.com/d/optout.
>
--
You received this message because you are subscribed to the Google Groups
"golang-nuts" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to golang-nuts+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
