[...] a copy *of* the pointed-to value.
On Wednesday, March 28, 2018 at 6:54:53 PM UTC+2, thwd wrote:
>
> Hi. Don't worry, I do get pointers and pass-by-value.
>
> I expected the expression (*x) to yield a copy to the pointed-to value.
>
> But, as you say, that happens on assignment.
>
> On Wednesday, March 28, 2018 at 6:50:06 PM UTC+2, Devon H. O'Dell wrote:
>>
>> 2018-03-28 9:39 GMT-07:00 Devon H. O'Dell <devon...@gmail.com>:
>> > CopyExplicitDeref gets a pointer to the struct in its receiver. If you
>> > have a pointer to T, then taking a pointer to the dereferenced T is a
>> > no-op: you get the pointer of the thing you just dereferenced. Any
>> > statement &*whatever will always yield the value of whatever. Copy
>> > happens on assignment, and no assignment occurs in this statement.
>>
>> I just realized that one additional thing that might be confusing is
>> that you're expecting CopyExplicitDeref to get a copy of _something_
>> since everything in Go is done by-value. Indeed, CopyExplicitDeref
>> does get a copy of something: the pointer to T. So if you change
>> CopyExplicitDeref to:
>>
>> func (t *T) CopyExplicitDeref() **T {
>> return &t
>> }
>>
>> and in main:
>>
>> a := &T{0}
>> b := a.CopyExplicitDeref()
>> fmt.Println(&a == b)
>>
>> you will see that it's actually the pointer that is copied.
>>
>> --dho
>>
>
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