On Wed, Dec 5, 2018 at 12:16 PM Burak Serdar <bser...@ieee.org> wrote:
> On Wed, Dec 5, 2018 at 10:12 AM Mark Volkmann <r.mark.volkm...@gmail.com>
> wrote:
> >
> > I can get a reflect.Type for a variable with the following: myType :=
> reflect.TypeOf(myVariable)
> >
> > How can I get a reflect.Type for a type I have defined?
> > For example: type MyThing struct { …bunch of fields… }
> > I need to get a reflect.Type that describes the MyThing type.
> >
> > The best I can find is this: myThingType :=
> reflect.TypeOf(new(MyThing)).Elem()
>
>
> myThingType:=reflect.TypeOf(MyThing{})
>
This works for concrete types, but not for interfaces or named channel and
function types.
For interfaces, you can use a nil pointer:
myThingType := reflect.TypeOf((*MyThing)(nil)).Elem()
For channels and functions, you don't need a pointer or the Elem() call:
myThingType := reflect.TypeOf(MyThing(nil))
The use of nil above is also good for named map type: the other suggestion
above will allocate an unused empty map (though the compiler may optimize
that away).
>
> >
> > I seems odd that I have to create one with new, getting a pointer to it,
> and then ask for the type of the thing in points to (with Elem) in order to
> get what I need.
> >
> > --
> > R. Mark Volkmann
> > Object Computing, Inc.
> >
> > --
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