Hi, I just want to achieve that one goroutine send a data and another
goroutine receive it and print it consequently, for instance o, 1, 2, 3.
Is there a correct way to achieve this ?
Regards
El jue., 24 ene. 2019 a las 23:08, Ian Denhardt (<i...@zenhack.net>)
escribió:
> In general, after the message send goes through, the two goroutines
> involved could start executing again in any order -- so the behavior
> you're seeing is expected?
>
> Is there a less toy example that this is supposed to be representative
> of? Or were you just expecting it to work differently, and trying to
> understand the behavior?
>
> It's hard to give advice without knowing what you're trying to achieve;
> If I wanted exactly the output you're going for I'd just do:
>
> for i := 0; i < 10; i++ {
> fmt.Printf("Producer %v\n", i)
> fmt.Printf("Consumer %v\n", i)
> }
>
> ..but I imagine that's not the point of the excercise.
>
> -Ian
>
> Quoting diego patricio (2019-01-24 16:48:35)
> > Hi, thanks for your response, still� I dont get right result
> > image.png
> > image.png
> >
> > El jue., 24 ene. 2019 a las 22:42, Christian Staffa
> > (<[1]christian.p.sta...@gmail.com>) escribió:
> >
> > Hi
> > to get a synchronization with goroutines you need to use an unbuffered
> > channel. you have used a buffered channel of 1.
> > Sent from my iPhone
> > On 24. Jan 2019, at 22:11, diego patricio <[2]dipas...@gmail.com>
> > wrote:
> >
> > Hi all, i'am just learning Go and goroutines, I have three goroutines
> > (main, producer, consumer) and I dont know how synchronize producer
> and
> > consumer for print one value at time, the output that I want is
> > Producer 0
> > Consumer 0
> > Producer 1
> > Consumer 1
> > ......
> > but the output of my program it's diferent.
> > the program:
> > <image.png>
> > The output:
> > <image.png>
> > Sorry about my english
> > Regards
> >
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