Yes, my fault. Thanks for pointing it out.
What happens if I remove the fmt.Printf function calls to have the
following code:
package main
import (
"fmt"
"runtime"
"time"
)
func main() {
count := runtime.GOMAXPROCS(1)
fmt.Printf("GOMAXPROCS: %d\n", count)
// goroutine 1
go func() {
for {
}
}()
// goroutine 2
go func() {
for {
}
}()
time.Sleep(10 * time.Second)
}
Can goroutine 1 or goroutine 2 be preempted? If yes, by which
mechanism?
On Friday, February 22, 2019 at 4:20:12 PM UTC+8, Ian Denhardt wrote:
>
> Quoting Jingguo Yao (2019-02-22 03:17:33)
> > Since both goroutines do not make any function calls
>
> fmt.Printf is a function.
>
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