Yes workers could regulate number of spawns with an atomic counter
themselves but how would the "master caller" sleep until all those workers
are done? It needs to sleep until the counter is zero, Like a WaitGroup.
22 Şub 2019 Cum 15:53 tarihinde Robert Engels <reng...@ix.netcom.com> şunu
yazdı:
> But you can replace waitempty() and related with a simple atomic counter
> variable and avoid channels for this. Far simpler.
>
> On Feb 22, 2019, at 6:38 AM, Serhat Sevki Dincer <jfcga...@gmail.com>
> wrote:
>
> A little imagination would help us all greatly. Select part would
> obviously be in a for loop. Like this:
>
> func worker() {
> // do work, prepare whatever
>
> for some_condition{
> // do stuff
>
> Select {
> ch <- true:
> go worker() // try to handover some jobs
> default:
> // max goroutine limit
> // do them yourself
> }
>
> // do stuff, increment counter
> }
>
> // do remaining jobs
>
> // make way
> <- ch
> return
> }
>
> 22 Şub 2019 Cum 15:30 tarihinde Robert Engels <reng...@ix.netcom.com>
> şunu yazdı:
>
>> I’m pretty sure this code is incorrect and there will only be a single
>> routine doing any “real work”, although the comment //do remaining jobs is
>> unclear because there is no code.
>>
>> > On Feb 22, 2019, at 12:42 AM, Serhat Şevki Dinçer <jfcga...@gmail.com>
>> wrote:
>> >
>> > Another use case is wait groups with Max number of goroutines allowed:
>> >
>> > ch:= make(chan bool, 10)
>> >
>> > func waiter() {
>> > ch <-true
>> > go worker()
>> >
>> > // when empty, all jobs are finished
>> > waitempty(ch)
>> > }
>> >
>> > func worker() {
>> > // do work
>> >
>> > Select {
>> > ch <- true:
>> > go worker() // try to handover some jobs
>> > default:
>> > // max goroutine limit
>> > // do them yourself
>> > }
>> >
>> > // do remaining jobs
>> >
>> > // make way
>> > <- ch
>> > return
>> > }
>> >
>> > --
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>>
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