I'm not sure if the log produce more than consume by the func 'centrale' in
the same period of time, will 'buff' be larger and larger and cost too much
memory.
For example, The log comes from network and write into a disk but network
speed is greater than disk write speed. So is there any way to control the
'buff' length.
On Sunday, March 17, 2019 at 12:02:06 AM UTC+8, Thomas S wrote:
>
> Hello,
>
> I have a software needing a lot of logs when processing.
>
> I need to :
> 1- Improve the processing time by doing non-blocking logs
> 2- Be safe with goroutines parallel logs
>
> fmt package doesn't match with (1) & (2)
> log package doesn't match with (1)
>
> *Here is my proposal. What do you think ?*
>
> *Design :*
>
> [Log functions] -----channel---->[Buffering function (goroutine)]
> ----channel----> [Printing function (goroutine)]
>
>
> package glog
>
> import (
> "container/list"
> "encoding/json"
> "fmt"
> )
>
> /*
> ** Public
> */
>
> func Println(data ...interface{}) {
> bufferChan <- fmt.Sprintln(data...)
> }
>
> func Print(data ...interface{}) {
> bufferChan <- fmt.Sprint(data...)
> }
>
> func Printf(s string, data ...interface{}) {
> go func() {
> r := fmt.Sprintf(s, data...)
> bufferChan <- r
> }()
> }
>
> /*
> ** Private
> */
>
> var bufferChan chan string
> var outChan chan string
>
> func init() {
> bufferChan = make(chan string)
> outChan = make(chan string)
> go centrale()
> go buffout()
> }
>
> func centrale() {
> var buff *list.List
> buff = list.New()
> for {
> if buff.Len() > 0 {
> select {
> case outChan <- buff.Front().Value.(string):
> buff.Remove(buff.Front())
> case tmp := <-bufferChan:
> buff.PushBack(tmp)
> }
>
> } else {
> tmp := <-bufferChan
> buff.PushBack(tmp)
> }
> }
> }
>
> func buffout() {
> for {
> data := <-outChan
> fmt.Print(data)
> }
> }
>
>
>
> It works well for now, I want to be sure to not miss anything as it's a
> very important part of the code.
>
> Thank you for your review.
>
>
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