On Sun, Dec 15, 2019 at 7:56 PM <smogg...@gmail.com> wrote:
>
> I'm having a similar problem as the original poster. I expect Buffered() to
> return the number of bytes that can be read from the current buffer, like the
> documentation states. However a call to Buffered() returns 0 both before and
> after a call to any Read() that finds bytes in the buffer. In my case the
> Reader is a net.Conn.
>
> How do we use Buffered() properly? This is the only google result I could
> find that even mentions using the function.
>
> I ended up solving my problem without using bufio.
Note that you are replying to an e-mail from over nine years ago.
The Buffered method is fairly special purpose. It just tells you how
many bytes you can Read without causing a call to the underlying
Reader. What are you really trying to do? Can you show us some code
that does not work as you expect?
Ian
> On Tuesday, August 24, 2010 at 6:21:20 PM UTC-4, Evan Shaw wrote:
>>
>> On Tue, Aug 24, 2010 at 5:17 PM, Archos <rau...@sent.com> wrote:
>> > Well, the doc. *on this case* didn't help me much:
>> >
>> > "Buffered returns the number of bytes that can be read from the
>> > current buffer."[1]
>>
>> I find that to be a pretty clear description. Consider that it could
>> be impossible or at least expensive to find the number of bytes in the
>> underlying io.Reader when all you have to go off of is the Read
>> method. How would you propose to do it with this type, for example:
>>
>> type nullReader struct{}
>>
>> func (r *nullReader) Read(p []byte) (int, os.Error) {
>> for i := range p {
>> p[i] = 0
>> }
>> return len(p), nil
>> }
>>
>> - Evan
>
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